i+u=(1x^2+1x+8)-(4x+1)

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Solution for i+u=(1x^2+1x+8)-(4x+1) equation:


Simplifying
i + u = (1x2 + 1x + 8) + -1(4x + 1)

Reorder the terms:
i + u = (8 + 1x + 1x2) + -1(4x + 1)

Remove parenthesis around (8 + 1x + 1x2)
i + u = 8 + 1x + 1x2 + -1(4x + 1)

Reorder the terms:
i + u = 8 + 1x + 1x2 + -1(1 + 4x)
i + u = 8 + 1x + 1x2 + (1 * -1 + 4x * -1)
i + u = 8 + 1x + 1x2 + (-1 + -4x)

Reorder the terms:
i + u = 8 + -1 + 1x + -4x + 1x2

Combine like terms: 8 + -1 = 7
i + u = 7 + 1x + -4x + 1x2

Combine like terms: 1x + -4x = -3x
i + u = 7 + -3x + 1x2

Solving
i + u = 7 + -3x + 1x2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1u' to each side of the equation.
i + u + -1u = 7 + -3x + -1u + 1x2

Combine like terms: u + -1u = 0
i + 0 = 7 + -3x + -1u + 1x2
i = 7 + -3x + -1u + 1x2

Reorder the terms:
i = 7 + -1u + -3x + 1x2

Simplifying
i = 7 + -1u + -3x + 1x2

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